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10a^2+9a-1=0
a = 10; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·10·(-1)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-11}{2*10}=\frac{-20}{20} =-1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+11}{2*10}=\frac{2}{20} =1/10 $
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